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A charged particle q is placed at the centre O of cube of length L(A B C D E F G H). Another same charge q is placed at a distance L from O. Then the electric flux through ABCD is A. (a) `q//4pi in_0L`B. (b) zeroC. (c) `q//2pi in_0L`D. (d) `q//3pi in_0L`

Answer» Correct Answer - B
Both the charges are identical and placed symmetrically about ABCD. The flux crossing ABCD due to each charge is `1/6[q/in_0]` but in opposite directions. Therefore the resultant is zero.


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