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A charged particle q is shot from a large distance twoards another charged particle Q which is fixed, with speed v. It approaches Q up to as closed distance r and then returns. If q were given a speed 2v, the distasnce of approach would be A. rB. `2r`C. `r//2`D. `r//4` |
Answer» Correct Answer - D `U_i+k_i=U_f+K_f` `0+1/2mv^2=1/4piepsilon_0.(Qq)/r+or rprop1/v^2` If v is doubled, the minimum distance r will remain `1/4` the. |
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