InterviewSolution
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InterviewSolution
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A charged particle with charge `q` enters a region of constant, uniform and mututally orthogonal fields `vec(E) and vec(B)` with a velocity `vec(v)` perpendicular to both `vec(E) and vec(B)`, and comes out without any change in magnitude or direction of `vec(v)`. ThenA. `vecv=vecBxxvecE//E^2`B. `vecv=vecExxvecB//B^2`C. `vecv=vecBxxvecE//B^2`D. `vecv=vecExxvecB//E^2` |
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Answer» Correct Answer - B When charged particle goes undefected, then `qE=qvB` or `v=E//B` The two forces acting on moving charged particle due to electric and magnetic fields oppose each other if `vecv` is along `vecExxvecB` Now, `v=(EB)/(B^2)=(EB sin 90^@)/(B^2)=(|vecExxvecB|)/(B^2)` `:. vecv=((vecExxvecB))/(B^2)` |
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