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    				| 1. | A chemical reaction is carried out by supplying 8 kJ of heat. The system performs the work of 2.7 kJ. Calculate ΔH and ΔU. | 
| Answer» Given : Q = + 8 kJ (since heat is absorbed by the system) W = -2.7 kJ (It will be a work of expansion) ΔH = ?, ΔU = ? ΔU = Q + W = 8 + (-2.7) = 5.3 kJ Internal energy of the system will increase by 5.3 kJ. Due to expansion, ΔV > 0, ΔH = ΔU + PΔV = 5.3 + 2.7 = 8 kJ Enthalpy of the system will increase by 8 kJ ∴ ΔU = 5.3 kJ, ΔH = 8 kJ | |