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A chemical reaction takes place in a container of cross sectional area 100 cm2. As a result of the reaction, a piston is pushed out through 10 cm against an external pressure of 1.0 bar. Calculate the work done by the system. |
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Answer» Given : Cross sectional area = A = 100 cm2 Displacement of a piston = 1 = 10 cm External pressure = P = 1.0 bar Work = W = ? Volume change = A × l ∴ ΔV = 100 × 10 = 1000 cm3 = 1 dm3 Work = W = -P × ΔV = -1 × 1 = -1 dm3 bar = – 1 × 100 J = -100 J ∴ Work = W = -100 J |
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