1.

A chemical reaction takes place in a container of cross sectional area 100 cm2. As a result of the reaction, a piston is pushed out through 10 cm against an external pressure of 1.0 bar. Calculate the work done by the system.

Answer»

Given : 

Cross sectional area = A = 100 cm2

Displacement of a piston = 1 = 10 cm

External pressure = P = 1.0 bar

Work = W = ?

Volume change = A × l 

∴ ΔV = 100 × 10 

= 1000 cm3

= 1 dm3

Work = W = -P × ΔV

= -1 × 1

= -1 dm3 bar

= – 1 × 100 J

= -100 J

∴ Work = W = -100 J



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