A chemist opened a couborad and found four bottles contaning water solutions, each of which had lost its label. Bottles 1,2,3 contained colourless solutions, while bottle 4 contained a blue solution. The lables from the bottles were lying scattered on the floor of the cupboard. They were:Copper (II) sulphate,""Hydrochloric acid Lead nitrate,""Sodium carbonate By mixing samples of the contents of the bottles, in pairs the chemist made the following observations: {:("Bottle +1 Bottle" 2 rarr, "White precipitate is formed"),("Bottle 1+ Bottle"3 rarr,"White precipitate is formed"),("Bottle 1+ Bottle" 4rarr,"White precipitate is formed"),("Bottle2+ Bottle"3rarr,"Colourless and odourless gas is evolved"),("Bottle 2+ Buttel" 4rarr,"No visivle reaction is observed"),("Bottle 3+ Bottle" 4rarr,"Blue precipitate is formed"):} With the help of the above observations answer the following questions. Which of the following bottle will give precipitate with bottle 1?

A chemist opened a couborad and found four bottles contaning water sol

1.	A chemist opened a couborad and found four bottles contaning water solutions, each of which had lost its label. Bottles 1,2,3 contained colourless solutions, while bottle 4 contained a blue solution. The lables from the bottles were lying scattered on the floor of the cupboard. They were:Copper (II) sulphate,""Hydrochloric acid Lead nitrate,""Sodium carbonate By mixing samples of the contents of the bottles, in pairs the chemist made the following observations: {:("Bottle +1 Bottle" 2 rarr, "White precipitate is formed"),("Bottle 1+ Bottle"3 rarr,"White precipitate is formed"),("Bottle 1+ Bottle" 4rarr,"White precipitate is formed"),("Bottle2+ Bottle"3rarr,"Colourless and odourless gas is evolved"),("Bottle 2+ Buttel" 4rarr,"No visivle reaction is observed"),("Bottle 3+ Bottle" 4rarr,"Blue precipitate is formed"):} With the help of the above observations answer the following questions. Which of the following bottle will give precipitate with bottle 1?
Answer» Bottle 2 Bottle 3 Bottle 4 All of these Solution :Bottle `4 RARR CuSO_(4)`, Bottle `2+` Bottle 3 `rarr HCI + Na_(2)CO_(3)` Bottle `1 rArr Pb(NO_(3))_(2)`, Bottle `+1` Bottle `4 rArr PbSO_(4) darr` Bottle `2 rArr HCI`, Bottle `3 rArr Na_(2)CO_(3)` (Since, HCI doesn't react with `CuSO_(4))`