1.

A chemist opened a cupboard and found four bottles containing water solutions, each of which had lost its label.Bottles 1,2,3 contanied colourless solution, while bottle 4 contained a blue solution.The labels from the bottles were lying scattered on the floor of the cupboard.They were: copper (II) sulphate, Hydrochloric acid lead nitrate , Sodium carbonate By mixing samples of the contents of the bottles, in pairs , the chemist made the following observations : Bottle 1 +Bottle 2 to White precipitate is formed. Bottle 1 +Bottle 3 to White precipitate is formed. Bottle 1 +Bottle 4 to White precipitate is formed. Bottle 2 +Bottle 3 to Colourless and odourless gas is evolved. Bottle 2 +Bottle 4 to No visible reaction is observed. Bottle 3 +Bottle 4 to Blue precipitate is formed. With the help of the above observations answer the following questions. Which one of the following bottles develops deep blue with aqueous ammonia ?

Answer»

Bottle 1
Bottle 2
Bottle 3
Bottle 4

Solution :Bottle 4 is `CuSO_4` and that GIVE deep BLUE colouration with excess of ammonia solution.
`Cu^(2+)(AQ)+4NH_3(aq)to[Cu(NH_3)_4]^(2+)` (intensive deep blue colour)(aq)


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