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A chemist was performing an experiment to study the effect of varying voltage on the velocity and de Broglie wavelength of the electrons. In first experiment, the electron was accelerated through a potential difference of 1kV and in second experiment, it was accelerated through a potential difference of 2kV. The wavelength of de Broglie waves associated with electron is given by: lamda=(h)/(sqrt(2qVm)) where, V is the voltage through which an electron is accelerated. Putting the values of h, m and q we get: lamda=(12.3)/(sqrt(V))Ã… Q. In order to get half velocity of electrons in second case, the applied potential will be: |
Answer» <html><body><p>0.25 kV<br/>2 kV<br/>0.5 kV<br/>0.75 kV</p>Answer :a</body></html> | |