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A chess match between two players A and B is won by whoever first wins a total of two games. Probability of A's winning, drawng and losing any particular game are 1/6, 1/3 and 1/2 respectively. (The game are independent). If the probability that B wins the match in the 4^(th)gams is p, then 6p is equal to |
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Answer» `=1/2xx1/6xx1/3xx1/2xx6+.^(3)C_(1)xx1/2xx1/3xx1/2xx1/2=6/72+3/36=(6+6)/72=1/6` |
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