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A chord is drawn passing through `P(2,2)` on the ellipse `(x^(2))/(25)+(y^(2))/(16) =1` such that it intersects the ellipse at A and B. Then maximum value of `PA.PB` isA. `(61)/(4)`B. `(59)/(4)`C. `(71)/(4)`D. `(63)/(4)` |
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Answer» Correct Answer - B Let equation of secant be `(x-2)/(cos theta) = (y-2)/(sin theta) =r` (Parametric form) Solving it with ellipse `((r cos theta+2)^(2))/(25)+((r sin theta +2)^(2))/(16)=1` `r^(2) (16 cos^(2) theta + 25 sin^(2) theta) +r (64 cos theta + 100 sin theta) - 236=0` `|r_(1)r_(2)| = PA. PB = |(-236)/(16 cos^(2)theta+25 sin^(2)theta)|` `=|-(236)/(16+9 sin^(2)theta)|` Max. `PA. PB = (236)/(16) = (59)/(4)` |
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