1.

Find the equation of the ellipse (referred to itsaxes as the axes of `xa n dy`, respectively) whose foci are `(+-2,0)`andeccentricity is `1/2`

Answer» Let the ellipse be `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1`
Given`e=(1)/(2)`
Also, foci of ellipse are `(+-ae,0)-=(+-2,0)`
`rArr ae=2 rArr a=4`
Now, `b^(2)=a^(2)(1-e^(2)) rArr b^(2) =12`
Therefore, equation of ellipse is `(x^(2))/(16)+(y^(2))/(12)=1`


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