1.

A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the minor segment.

Answer»

∴length of chord = 2√(OA²-OP²)

= 2√(10²-10²⁄2)

= 2√(100-100⁄2)

= 2√(100-50)

= 2√(50)

= 2×7.07

= 14.14cm Ans



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