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A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the minor segment. |
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Answer» ∴length of chord = 2√(OA²-OP²) = 2√(10²-10²⁄2) = 2√(100-100⁄2) = 2√(100-50) = 2√(50) = 2×7.07 = 14.14cm Ans |
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