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A chord of a circle subtends an angle of θ at the centre of the circle. The area of the minor segment cut off by the chord is one eighth of the area of the circle. Prove that 8 sin θ2 cos θ2+π=πθ45 |
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Answer» A chord of a circle subtends an angle of θ at the centre of the circle. The area of the minor segment cut off by the chord is one eighth of the area of the circle. Prove that 8 sin θ2 cos θ2+π=πθ45 |
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