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A circle is inscribed in a rhombus ABCD with oneangle 60° The distance from the centre of thecircle to the nearest vertex is equal to 1. If P Is anypoint of the circle, then |PA|2 + |PB|2 + |PC|2 +IPD? equals

Answer» A circle is inscribed in a rhombus ABCD with one
angle 60° The distance from the centre of the
circle to the nearest vertex is equal to 1. If P Is any
point of the circle, then |PA|2 + |PB|2 + |PC|2 +
IPD? equals


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