1.

A circle with radius `2` is placed against a right angle. A smaller circle is also placed as shown in the adjoining figure. The radius of the smaller circle is:

Answer» Let the radius of the larger circle is `R` and radius of the smaller circle is `r`.
We can create a diagram with the given details. Please refer to video for the diagram.
From the diagram, we can say that,
`R^2+R^2 = (R+2r)^2`
`=>2R^2 = (R+2r)^2`
`=>R+2r = sqrt2R`
`=>2r = sqrt2R-R`
`=> r = (R(sqrt2-1))/2`
We are given, `R = 2`,
`:. r = sqrt2 -1`
So, radius of smaller circle will be `sqrt2-1`.


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