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A circuit is arranged as shown. Then, the current from `A` to `B` is A. `+ 500 mA`B. `+ 1.5 mA`C. `- 250 mA`D. `- 500 mA` |
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Answer» Correct Answer - A (a) `I = (sum (E // r))/(1 + R sum (1//r))` `= ((5)/(15) + (10)/(10))/(1 + 10 [ (1)/(15) + (1)/(10)]) = (1)/(2) A = 500 mA` |
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