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A circuit is shown in the figure below. Find out the charge of the condenser having capacity `5muF` A. `4.5muC`B. `9muC`C. `7muC`D. `30muC` |
Answer» Correct Answer - B From figure, charge on condenser of capacity `3muF` is, `Q_(1)=C_(1)V=3xx10^(-6)xx6=18xx10^(-6)C`. Thus, p.d. across `C_(1)` is, `V_(1)=(VC_(p))/(C_(1)+C_(p))" ""where"" "C_(p)=2+5=7muF` `=(7xx6)/10=4.2V` Thus, p.d. across `C_(p)` is, 1.8 V Now, charge on `5muF` condenser is, `Q_(2)=5xx10^(-6)xx1.8=9muC` |
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