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A circular coil of `100` turns and having a radius of `0*05m` carries a current of `0*1A`. Calculate the work required to turn the coil in an external magnetic field of `1*5T` through `180^@` about an axis perpendicular to the magnetic field. The plane of the coil is initially at right angles to the magnetic field. |
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Answer» Correct Answer - `0*24J` Here, `n=100`, `r=0*05m`, `I=0*1A` `W=?`, `B=1*5T`, `theta_1=0^@`, (When plane of coil is at `90^@` to B) `theta_2=180^@` `M=nIA=nI(pir^2)` `=100xx0*1(3*14)(0*05)^2` `=7*85xx10^-2Am^2` `W=-MB(costheta_2-costheta_1)` `=-7*85xx10^-2xx1*5(cos180^@-cos0^@)` `W=0*24J` |
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