A circular coil of `20turns` and radius `10cm` carries a current of `5A`. It is placed in a uniform magnetic field of `0*10T`. Find the torque acting on the coil when the magnetic field is applied (a) normal to the plane of the coil (b) in the plane of coil. Also find out the total force acting on the coil.

A circular coil of `20turns` and radius `10cm` carries a current of `5

1.	A circular coil of `20turns` and radius `10cm` carries a current of `5A`. It is placed in a uniform magnetic field of `0*10T`. Find the torque acting on the coil when the magnetic field is applied (a) normal to the plane of the coil (b) in the plane of coil. Also find out the total force acting on the coil.
Answer» Here, `n=20`, `r=010m`, `I=5A`, `B=010T` Area of each turn of coil, `A=pir^2=22/7xx(01)^2=00314m^2` Torque acting on the coil, `tau=nIAB sin alpha` (a) Here, `alpha=0^@` so `tau=20xx5xx(00314)xx01xxsin0^@=0` (b) Here, `alpha=90^@` so `tau=20xx5xx(00314)xx01xxsin90^@=0*314N-m`. Coil carrying current acts as a magnetic dipole. The force acting on magnetic dipole in a uniform magnetic field is zero.

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