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A circular coil of `300` turns and diameter `14cm` carries a current of `15A`. What is the magnitude of magnetic moment linked with the loop? |
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Answer» Here, `N=300`, `r=14/2cm=7xx10^-2m, I=15A` `M=NIA=NI(pir^2)` `=300xx15xx3*14(7xx10^-2)^2=69*2Am^2` |
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