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A circular coil of radius 8.0 cm and 20 turns is rotated about its vertical diameter with an angular speed of 50 rad s^(-1) in a uniform horizontal magnetic field of magnitude 3.0 xx 10^(-2) T. Obtain the maximum and average emf induced in the coil. If the coil forms a closed loop of resistance 10Omega, calculate the maximum value of current in the coil. Calculate the average power loss due to Joule heating. Where does this power come from ? |
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Answer» Solution :Letbeadmove oncircular PATHOF radiusRwithangularvelocity `epsilon ` Let NBE normalreaction At anyinstantpositionof beadbe A Directionof normalforceis towarddirection AOTwocomponentof N are N cos `theta`and N sin `theta `  Considerequilibrium of beadat point A N cos `theta` =mg N sin `theta = m Repsilon ^(2) sinepsilon` m R `epsilon^(2) sintheta`is horizontalcomponentofcentripetalforce N cos`theta` = mg cos `theta= ( g)/( R epsilon^(2))` Whenbead is atlowermostposition`theta=0 ^ (@)` `g= R epsiloon ^(2)` `epsilon= sqrt((g )/( R))` If`=sqrt((2 g)/( R ))` thenfrom EQUATION(4 ) `cos theta= (g )/( R epsilon ^(2)) = (g ) /(R ) xx (R ) /(2G)` `cos theta= (1)/( 2)` `theta = 60^(@)` |
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