1.

A circular coil of radius `R` carries a current `i`. The magnetic field at its centre is `B`. The distance from the centre on the axis of the coil where the magnetic field will be `B//8` isA. `sqrt(2)R`B. `sqrt(3)R`C. `2R`D. `3R`

Answer» Correct Answer - 2
`B=(mu_(0)nir^(2))/(2(r^(2)+x^(2))^(3//2))=(1)/(8)xx(mu_(0)ni)/(2r)`


Discussion

No Comment Found

Related InterviewSolutions