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A circular coil of radius `R` carries a current `i`. The magnetic field at its centre is `B`. The distance from the centre on the axis of the coil where the magnetic field will be `B//8` isA. `sqrt(2)R`B. `sqrt(3)R`C. `2R`D. `3R` |
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Answer» Correct Answer - 2 `B=(mu_(0)nir^(2))/(2(r^(2)+x^(2))^(3//2))=(1)/(8)xx(mu_(0)ni)/(2r)` |
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