InterviewSolution
Saved Bookmarks
| 1. |
A circular coil of wire consisting of 100 turns, each of radius `8*0cm` carries a current of `0*40A`. What is the magnetude of the magnetic field `vecB` at the centre of the coil? |
|
Answer» Here, `n=100`, `r=8*0xx10^-2m`, `I=0*40A`, `B=?` `B=(mu_0)/(4pi)(2pinI)/(r)=10^-7xx2xx(22)/(7)xx(100xx0*4)/(8xx10^-2)=3*1xx10^-4T` |
|