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A circular current carrying loop of radius R, carries a current l. The magnetic field at a point on the axis of coll is `(1)/(sqrt(8))` times the value of magnetic field at the centre. Distance of point from centre isA. `(R )/(sqrt(2))`B. `(R )/(sqrt(3))`C. `Rsqrt(2)`D. R |
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Answer» Force on the dielectric `=(epsilon_(0)bv^(2)(k-1))/(2d)` If rise due to this force be `x_(1)` then `=(epsilon_(0)bv^(2)(k-1))/(2d)=(dL)x_(1)pg` Then `x_(2)` is the rise due to surface tension `T((1)/(r_(1))+(1)/(r_(2)))=T((1)/(oo)+(1)/(d//2))=(2T)/(d)=(x_(2))pg` `x_(1)+x_(2)=(epsilon_(0)bv^(2)(k-1))/(2d^(2)Lpg)+(2T)/(dpg)=5+2=7mm` |
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