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A circular current loop of magnetic moment M is in an arbitrary orientation in an external magnetic field B. The work done to rotate the loop by 30° about an axis perpendicular to its plane is(a) MR (b) √ MR/2 (C) MB/2 (d) zero. |
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Answer» The work done to rotate the loop by 30° about an axis perpendicular to its plane is zero. |
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