1.

A circular disc of radius r and mass m rotates about the axis passing through the centre and perpendicular to its plane. What will if rotational kinetic energy?

Answer»

`(1)/(4)mromega^(2)`
`(1)/(2)mromega^(2)`
`(1)/(4)mr^(2)omega^(2)`
`(1)/(2)mr^(2)omega^(2)`

Solution :Rotational kinetic ENERGY = `(1)/(2)IOMEGA^(2)`
`=(1)/(2)xx(mr^(2))/(2)xxomega^(2)`
`=(1)/(4)mr^(2)omega^(2)`


Discussion

No Comment Found