A circular disc with a groove along its diameter is placed horizontally . A block of mass 1 kg is placed asshown . The coefficient of friction between the block and all surfaces of groove in contact is mu = 2//5 . The disc has an acceleration of 25 m//s^(2) . find the acceleration of the block with respect to disc .

A circular disc with a groove along its diameter is placed horizontall

1.	A circular disc with a groove along its diameter is placed horizontally . A block of mass 1 kg is placed asshown . The coefficient of friction between the block and all surfaces of groove in contact is mu = 2//5 . The disc has an acceleration of 25 m//s^(2) . find the acceleration of the block with respect to disc .
Answer» Solution : N + ma SIN `THETA = "mg cos" theta` N = ( mg cos `theta - "ma sin" theta )` Acceleration of mass w.r. to disc ` a_(0) = (( "mg sin "theta + "ma cos" theta - muN)/(m))`