A circular dise in rolling down in an inclined plane without slipping. The percentage of rotational energy in its total energy is

A circular dise in rolling down in an inclined plane without slipping.

1.	A circular dise in rolling down in an inclined plane without slipping. The percentage of rotational energy in its total energy is
Answer» `66.61%` `33.33%` `22.22%` `50%` SOLUTION :Rotational `K.E=(1)/(2)lomega^(2)=(1)/(2)((1)/(2)MR^(2)) omega^(2)=(1)/(4) MR^(2) omega^(2)` Translational `K.E.=(1)/(2) MV^(2)=(1)/(2)M(R omega)^(2)=(1)/(2) MR^(2) omega^(2)` Total kinetic energy `=E_("rot")+E_("trans")=(1)/(4)MR^(2) omega^(2)=(3)/(4) MR^(3)MR^(2) omega^(2)` `% "of" E_("rot") =(E_("rot"))/(E_("rot"))xx100%=33.33%`