A circular loop of radius 3 cm is having a current of 12.5 A. The magnitude of magnetic field at a distance of 4 cm on its axis isA. `5.65 xx 10^(-5)T`B. `5.27 xx 10^(-5)T`C. `6.54 xx 10^(-5)T`D. `9.20 xx 10^(-5)T`

A circular loop of radius 3 cm is having a current of 12.5 A. The magn

1.	A circular loop of radius 3 cm is having a current of 12.5 A. The magnitude of magnetic field at a distance of 4 cm on its axis isA. `5.65 xx 10^(-5)T`B. `5.27 xx 10^(-5)T`C. `6.54 xx 10^(-5)T`D. `9.20 xx 10^(-5)T`
Answer» Correct Answer - A `B=(mu_(0)IR^(2))/(2(R^(2)+x^(2))^(3//2))` Here, I = 12.5 A, R = 3 cm = `3xx10^(-2)m` x = 4 cm = `4xx10^(-2)m` `therefore" "B=(4pixx10^(-7)xx12.5xx(3xx10^(-2))^(2))/(2[(3xx10^(-2))^(2)+(4xx10^(-2))^(2)]^(3//2))=5.65xx10^(-5)T`

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A circular loop of radius 3 cm is having a current of 12.5 A. The magnitude of magnetic field at a distance of 4 cm on its axis isA. `5.65 xx 10^(-5)T`B. `5.27 xx 10^(-5)T`C. `6.54 xx 10^(-5)T`D. `9.20 xx 10^(-5)T`

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