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A circular path has to be constructed around a circular ground. If the areas of the outer and inner circles are 1386 m2 and 616 m2 respectively, find the width and area of the path. |
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Answer» Area of the outer circle = 1386 m2 πR2 = 1386m2 Area of the inner circle = 616 m2 πr2 = 616m2 Area of the path = Area of outer circle – Area of the inner circle 1386 m2 – 616 m2 Area of the path = 770m2 Also πR2 = 1386 R2 = \(\frac{1386\times7}{22}\) R2 = 63 x 7 R2 = 9 x 7 x 7 R2 = 32 x 72 R = 3 x 7 Outer Radius R = 21 m Again πr2 = 616 \(\frac{22}{7}\) x r2 = 616 r2 = 28 x 7 r2 = 4 x 7 x 7 r2 = 22 x 72 r = 2 x 7 Inner radius r = 14m Width of the path = Outer radius – Inner radius = 21 – 14 Width of the path = 7m |
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