1.

A circular path has to be constructed around a circular ground. If the areas of the outer and inner circles are 1386 m2 and 616 m2 respectively, find the width and area of the path.

Answer»

Area of the outer circle = 1386 m2

πR2 = 1386m2

Area of the inner circle = 616 m2

πr2 = 616m2

Area of the path = Area of outer circle – Area of the inner circle

1386 m2 – 616 m2

Area of the path = 770m2

Also πR2 = 1386

R2 = \(\frac{1386\times7}{22}\)

R2 = 63 x 7

R2 = 9 x 7 x 7

R2 = 32 x 72

R = 3 x 7

Outer Radius R = 21 m

Again πr2 = 616

\(\frac{22}{7}\) x r2 = 616

r2 = 28 x 7 

r2 = 4 x 7 x 7 

r2 = 22 x 72 

r = 2 x 7 

Inner radius r = 14m 

Width of the path = Outer radius – Inner radius 

= 21 – 14 

Width of the path = 7m



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