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A circular section cable has a tensile force of 1 kN applied to it and the force produces a stress of 7.8 MPa in the cable. Calculate the diameter of the cable. |
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Answer» Stress \(\sigma\) = \(\cfrac{forcce F}{area A}\) hence, cross-sectional area, A = \(\cfrac{forcce F}{stress\,\sigma}\) = \(\cfrac{1\times10^3}{7.8\times10^6}\) = 128.2 x 10-6 m2 Circular area = \(\pi\)r2 = 128.2 x 10-6 m2 from which, r2 = \(\cfrac{128.2 \times10^{-6}}{\pi}\) and radius r = \(\sqrt{\cfrac{128.2 \times10^{-6}}{\pi}}\) = 6.388 10-3 m = 6.388 mm and diameter d = 2 x r = 2 x 6.388 = 12.78 mm |
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