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A circular segment of radius `20cm` subtends an angle of `60^@` at its centre. Figure A current of `10A` is flowing through it. Find the magnitude and direction of the magnetic field produced at the centre. |
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Answer» Correct Answer - `5*2xx10^-6T` Let `hatn` be a unit vector perpendicular to the plane of paper upwards. Then total magnetic field at O due to current through the given structur is `vecB=vecB_(ab)+vecB_(bc)+vecB_(cd)=0+(mu_0)/(4pi)I/rtheta(-hatn)+0` [As point O lies on the wire ab and cd, so `B_(ab)=0=B_(cd)`] `:. B=(mu_0)/(4pi)I/rtheta=10^-7xx(10)/((20xx10^-2))xxpi/3` `=5*2xx10^-6T` |
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