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A class consist of 30 boys and 20 girls of which half the girls have blue eyes. Find the probability that a certain student chosen at random is a boy or has blue eyes. |
Answer» Total number of boys `= 30` Total number of girls ` = 20` Total number of students ` = 30+20 = 50` Total number of students having blue eyes ` = 30/2+20/2 = 25` Total number of students who are boys and have blue eyes ` = 30/2= 15` Probability that a student chosen is boy, `P(A) = 30/50 = 3/5` Probability that a student chosen is blue eyed, `P(B) = 25/50 = 1/2` Probability that a student chosen is a boy and blue eyed, `P(AnnB) = 15/50 = 3/10` Probability that a student chosen is a boy or blue eyed, `P(AuuB) = P(A)+P(B)-P(AnnB) = 3/5+1/2-3/10 = 8/10 = 4/5` |
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