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A classroom is 11 m long, 8 m wide and 5 m high. Find the sum of the areas of its floor and the four walls (including doors, windows etc.) |
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Answer» Given details are, Dimensions of class room = 11m × 8m × 5m Where, Length = 11m, Breadth = 8m, Height = 5m We know, Area of floor = length × breadth = 11 × 8 = 88 m2 Area of four walls (including doors & windows) = 2 (lh + bh) cm2 = 2 (11×5 + 8×5) = 2 (55 + 40) = 2 (95) = 190m2 ∴ Sum of areas of floor and four walls = area of floor + area of four walls = 88 + 190 = 278 m2 |
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