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A clock has a hour hand of `5 cm` long find the magnitude of avg. velocity of tip of hour hand between `2: 00 a.m.` to `4.00 p.m`A. `30 cm//hr`B. `(5pi)/(12) cm//hr`C. `(5)/(14) cm//hr`D. `(5pi)/(84). Cm//hr` |
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Answer» Correct Answer - C Average velocity = Displacement/ time. |
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