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A closed circuit is in the form of a regular hexagon of side r. If the circuit carries current I, what is the magnetic field induction at the centre of the hexagon?A. `(sqrt(3)mu_(0)I)/(4pia)`B. `(sqrt(3)mu_(0)I)/(2pia)`C. `(sqrt(3)mu_(0)I)/(3pia)`D. `(sqrt(3)mu_(0)I)/(pia)` |
Answer» Correct Answer - 4 Magnetic field at `O` due to `AB, i.e` `B=(mu_(0)I)/(4pid)(sinphi_(1)+sinphi_(2))` |
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