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A closed organ pipe of length L is vibrating in its first overtone there is a point Q inside the pipe at a distance `7L//9` form the open end the ratio of pressure amplitude at Q to the maximum pressure amplitude in the pipe isA. `1:2`B. `2:1`C. `1:1`D. `2:3` |
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Answer» Correct Answer - A `DeltaPm=2DeltaP_(0) coskx` (assuming closed end as origin) At point `Q,x=L-(7L)/9=(2L)/9` `DeltaPm=2DeltaP_(0)cos((2pi)/(lamda)xx(2L)/9)=DeltaP_(0)` `:.` Required ratio `=1:2` |
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