1.

A closed organ pipe of radiusr_(1) and an open organ pipe of radius r_(2) and having same length 'L' resonate when exited with a given tuning fork. Closed organ pipe and open organ pipe resonates in fundamental mode, then :

Answer»

`1.2 (r_(2)-r_(1)) =L`
`r_(2)-r_(1)=L`
`r_(2)-2r_(1) = 2.5L`
`2r_(2)-r_(1) = 2.5L`

SOLUTION :With END correction for closed organ pipe
`implies (lambda)/4 = L+e`
and for open organ pipe `(lambda)/2 = L + 2e_(2)`
SO `4(L+e_(1))=2(L+2e_(2))`
Now, `e_(1) = 0.6 r_(1)`
and `e_(2) = 0.6 r_(2)`
`2L = 4(e_(2)-e_(1))`
`L = 2(e_(2)-e_(1))`
`=2 xx 0.6 (r_(2)-r_(1))`
`L = 1.2 (r_(2)-r_(1))`.


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