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A closely wound solenoid of 2000 turns and area of cross-section 1.6 × 10-4 m2 , carrying a current of 4.0 A, is suspended through its centre allowing it to turn in a horizontal plane.1. What is the magnetic moment associated with the solenoid?2. What is the force and torque on the solenoid if a uniform horizontal magnetic field of 7.5 × 10-2 is set up at an angle of 30° with the axis of the solenoid? |
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Answer» 1. Magnetic dipole moment, M = nIA = 2000 × 4.0 × 1.6 × 10-4 = 1.28 JT-1 2. Net force = 0 Torque, τ = MB sinθ = 1.28 × 7.5 × 10-2 × sin 30° = 1.28 × 7.5 × 10-3 × 1/2 = 4.8 × 10-2 Nm. |
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