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| 1. |
A closes organ pipe of length 20 cm is sounded with a tuning fork in resonance. What is the frequency of the tuning fork? (v = 332 m/s) |
| Answer» Solution :In resonance , the FREQUENCY of the FORK is equal to the frequency of the organ pipe `f = (V)/(4L) = (332)/(4 xx 0.2) = 415` Hz | |