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A code word is to consist of two distinct English alphabets followed bytwo distinct number from `1to9.`for example, `C A23`is a code word. How many such code words are there? How many of them endwith an even integer? |
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Answer» (i) We know that there are 26 letters in the English alphabet. number of ways of choosing 2 letters out of 26 `=""^(26)P_(2)=(26xx25)=650.` Number of ways of choosing 2 numbers out of 9 `=""^(9) P_(2)=(9xx8)=72.` By the fundamental principle of multiplication, the total number of codes `=(650xx72)=46800.` (ii) Particular case When each code ends with an even integer In this case, it can have any of the numbers 2, 4, 6, 8 at the extreme right position. This position can thus be filled in 4 ways. The next left position can be filled with any of the remaining 8 numbers. So, there are 8 ways of filling this position. Number of ways of choosing pairs of even numbers `=(4xx8)=32.` Number of ways of choosing 2 letters out of 26 `=""^(26)P_(2)=(26xx25)=650.` Hence , the number of such codes which end with an even Integer `=(32xx650)=20800.` |
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