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A coil has a self-inductance of 12.00 ml, and the current through it changes from 0.190-A to 1.80-A in 0.90 s. Find the magnitude of the average induced emf in the coilduring this period.N |
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Answer» Given, self-inductance, L=0.05 HenryRate of change of current, dtdi =100As −1 Let, Magnitude of e.m.f. EWE know that, L= di/dte 0.05= ∣∣∣∣ 100E ∣∣∣∣ ∣e∣=5V |
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