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A coil having inductance 2.0 H and resistance `20 Omega` is connected to a battery of emf 4.0 V. Find (a) the current a the instant 0.20 s after the connection Is made and (b) the magnetic energy at this instant.A. 0.45 A, 0.3 JB. 0.6 A, 5 JC. 0.17 A, 0.03 JD. 0.1 A, 0.3 J |
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Answer» Correct Answer - C `I=I_(0) (1-e^(-Rt//2))` `I_(0)=(4.0)/(20)=0.2A` ` I=0.2 (1-e^(-(20xx0.2)/(2)))` `I=0.17A` `E_(B)=(1)/(2)LI^(2)=0.02J` |
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