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A coil of `100` turns, each of area `0.02m^(2)` is kept in a uniform field of induction `3.5xx10^(-5)`T. If the coil rotates with a speed of `6000r.p.m.` about an axis in the plane of the coil and perpendicular to the magnetic induction, calculate peak value of e.m.f. indcued in the coil |
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Answer» Given: `n=100`, `A=0.02m^(2)`, `B=3.5xx10^(-5)T`, `f=6000 r.p.m=(6000)/(60)r.p.s. e_(max)=?` Induced e.m.f. in a rotating coil, `e=2pifBnAsinomegat` `e_(max)=2pifBnA` `=2pi(6000)/(60)xx3.5xx10^(-5)xx100xx0.02` `=2xx(22)/(7)xx3.5xx2xx10^(-3)` `=0.044` volt. |
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