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A coil of 500 turns and mean radius 10 cm makes 3000 rotations per minute about one of its diameter in a uniform magnetic field of induction `4xx10^(-2)Wb//m^(2)` perpendicular to its axis of rotation. The rms current through the coil if its resistance is 100 `Omega`, isA. 4.1AB. 1.4AC. 4.4AD. 1.1A |
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Answer» Correct Answer - B `e_(0)=nAB2pif` `I_(rms)=(e_(rms))/(R)` `=(e_(0))/(Rsqrt(2))=(nAB2pif)/(Rsqrt(2))` `=(500xx3.14xx10^(-2)xx4xx10^(-2)xx2xx3.14xx50)/(100xx1.414)` `=1.4A` |
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