1.

A coil of cross sectional area 100 `cm^(2)` is placed in the magnetic field, which changes to `4xx10^(-2)Wb//cm^(2)` within 5s. What will be the current across `5Omega` resistance?A. 0.016 AB. 0.16 AC. 1.6 AD. 16.0 A

Answer» Correct Answer - B
`e=A(dB)/(dt)`
`=(100xx10^(-4)xx4xx10^(2))/(5)=0.8V`
`I=(e)/(R)=(0.8)/(5)=0.16A`


Discussion

No Comment Found

Related InterviewSolutions