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A coil of inductance `L=5H` and resistance `R=55Omega` is connected in series to the mains alternating voltage of frequency `f=50Hz` in series. What can be the non-zero capacitance of the capacitor (in `muF`) connected in series with the coil, if the power dissipated has to remain unchanged. (take `pi^(2)=10`) |
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Answer» Correct Answer - 1 `P_(av)=VI cos phi = V (V/z)=(R/z)=(V^(2)R)/(Z^(2))` It means `Z` has to be same in both cases `Z_(1)=Z_(2)impliessqrt(R^(2)+X_(L)^(2))=sqrt(R^(2)+(X_(C)-X_(L))^(2))` `2X_(L)=X_(C)` `impliesC=1/(2omega^(2)L)=10^(-6)=1xx10^(-6)` |
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