InterviewSolution
Saved Bookmarks
| 1. |
A coil of self inductance 3 H and resistance 100 Ω carries a steady current of 2 A. (a) What is the energy stored in the magnetic field of the coil?(b) What is the energy per second dissipated in the resistance of the coil ? |
|
Answer» Data : L = 3 H, R = 100 Ω, I = 2 A (a) Magnetic energy stored, Um = \(\cfrac12\)LI2 = \(\cfrac12\)(3) (2)2 = 6 J (b) Power dissipated in the resistance of the coil, P = I2R = (2)2 (100) = 400 W |
|