1.

A coil of self inductance 3 H and resistance 100 Ω carries a steady current of 2 A. (a) What is the energy stored in the magnetic field of the coil?(b) What is the energy per second dissipated in the resistance of the coil ?

Answer»

Data : L = 3 H, R = 100 Ω, I = 2 A 

(a) Magnetic energy stored,

Um\(\cfrac12\)LI2 = \(\cfrac12\)(3) (2)2 = 6 J

(b) Power dissipated in the resistance of the coil,

P = I2R = (2)2 (100) = 400 W



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