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A coil suspended freely in a radial magnetic field rotates through 30° when a current of 30 A is passed through it. Through what angle will it rotate if the current is doubled and the magnetic induction is halved? |
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Answer» The angle of rotation, θ ∝ IB (in the usual notation) As I2B2 = (2I1) \(\left(\cfrac{B_1}2 \right)\) = I1B1, the angle of rotation will be the same, i.e., 30°. |
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