A coin and six faced die, both unbiased are thrown simultaneously. The

1.	A coin and six faced die, both unbiased are thrown simultaneously. The probability of getting a tail on the coin and an even number on the die is(a) \(\frac{1}{2}\) (b) \(\frac{3}{4}\)(c) \(\frac{1}{4}\)(d) \(\frac{2}{3}\)
Answer» (c) \(\frac{1}{4}\) Let A : Event of getting a tail on the coin B : Event of getting an even number on the die. Then, P(A) = \(\frac{1}{2}\) P(B) = \(\frac{3}{6}\) = \(\frac{1}{2}\) as B = {2,4,6} A and B being independent events, P(Getting tail on the coin and even number on the die) = P(A ∩ B) = P(A) × P(B) = \(\frac{1}{2}\)x\(\frac{1}{2}\) = \(\frac{1}{4}\).

A coin and six faced die, both unbiased are thrown simultaneously. The probability of getting a tail on the coin and an even number on the die is(a) \(\frac{1}{2}\) (b) \(\frac{3}{4}\)(c) \(\frac{1}{4}\)(d) \(\frac{2}{3}\)

Answer»

(c) \(\frac{1}{4}\)

Let A : Event of getting a tail on the coin

B : Event of getting an even number on the die.

Then, P(A) = \(\frac{1}{2}\)

P(B) = \(\frac{3}{6}\) = \(\frac{1}{2}\) as B = {2,4,6}

A and B being independent events,

P(Getting tail on the coin and even number on the die)

= P(A ∩ B) = P(A) × P(B) = \(\frac{1}{2}\)x\(\frac{1}{2}\) = \(\frac{1}{4}\).

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A coin and six faced die, both unbiased are thrown simultaneously. The probability of getting a tail on the coin and an even number on the die is(a) \(\frac{1}{2}\) (b) \(\frac{3}{4}\)(c) \(\frac{1}{4}\)(d) \(\frac{2}{3}\)

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